What is the answer to 5^{2x}-5^x+1=0 ?

The answer to 5^{2x}-5^x+1=0 is No Solution for x\in\mathbb{R}

Solve for x: 5^{2x}-5^x+1=0

The solution is No Solution for x\in\mathbb{R}

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5^{2 x} - 5^{x} + 1 = 0

No Solution for x \in R

Solution steps

5^{2 x} - 5^{x} + 1 = 0

Apply exponent rules

(5^{x})^{2} - 5^{x} + 1 = 0

Rewrite the equation with

5^{x} = u

(u)^{2} - u + 1 = 0

Solve

u^{2} - u + 1 = 0 :

No Solution for

u \in R

No Solution for x \in R

5^{x} = 60

(\frac{1}{2})^{x - 1} = 32

4^{2 x + 5} = 64

y, 6^{3} x 6^{5} = x^{y}

x, e^{z x} = x yz

What is the answer to 5^{2x}-5^x+1=0 ?
The answer to 5^{2x}-5^x+1=0 is No Solution for x\in\mathbb{R}
Solve for x: 5^{2x}-5^x+1=0
The solution is No Solution for x\in\mathbb{R}