What is the answer to 10^{x-1}=8*3^x ?

The answer to 10^{x-1}=8*3^x is x=(ln(80))/(ln(10)-ln(3))

Solve for x: 10^{x-1}=8*3^x

The solution is x=(ln(80))/(ln(10)-ln(3))

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1 0^{x - 1} = 8 \cdot 3^{x}

x = \frac{ln ( 80 )}{ln ( 10 ) - ln ( 3 )}

Solution steps

1 0^{x - 1} = 8 \cdot 3^{x}

Apply exponent rules

(x - 1) ln (10) = ln (8) + x ln (3)

Solve

(x - 1) ln (10) = ln (8) + x ln (3) : x = \frac{ln ( 80 )}{ln ( 10 ) - ln ( 3 )}

x = \frac{ln ( 80 )}{ln ( 10 ) - ln ( 3 )}

x = e^{1 - x}

800 = 60 (1.25)^{x}

21 6^{2 x - 3} = 3 6^{- x + 7}

4^{3 x + 4} = 3 2^{x - 1}

57 = 1 7^{x}

What is the answer to 10^{x-1}=8*3^x ?
The answer to 10^{x-1}=8*3^x is x=(ln(80))/(ln(10)-ln(3))
Solve for x: 10^{x-1}=8*3^x
The solution is x=(ln(80))/(ln(10)-ln(3))