What is the answer to 5^{2x-1}=9^x ?

The answer to 5^{2x-1}=9^x is x=(ln(5))/(2(ln(5)-ln(3)))

Solve for x: 5^{2x-1}=9^x

The solution is x=(ln(5))/(2(ln(5)-ln(3)))

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5^{2 x - 1} = 9^{x}

x = \frac{ln ( 5 )}{2 ( ln ( 5 ) - ln ( 3 ) )}

Decimal Notation

x = 1.57533 \dots

Solution steps

5^{2 x - 1} = 9^{x}

Apply exponent rules

(2 x - 1) ln (5) = x ln (9)

Solve

(2 x - 1) ln (5) = x ln (9) : x = \frac{ln ( 5 )}{2 ( ln ( 5 ) - ln ( 3 ) )}

x = \frac{ln ( 5 )}{2 ( ln ( 5 ) - ln ( 3 ) )}

x^{5 x^{5}} = 3 6^{3}

2^{x} = 62.06896552

4^{x - 2} = 2^{x + 1}

x - 50 e^{(- \frac{x}{200})} = 175

ln (1 + x^{x}) = 0

What is the answer to 5^{2x-1}=9^x ?
The answer to 5^{2x-1}=9^x is x=(ln(5))/(2(ln(5)-ln(3)))
Solve for x: 5^{2x-1}=9^x
The solution is x=(ln(5))/(2(ln(5)-ln(3)))