What is the answer to 4^{-x}=2^{x^2+2x-8} ?

The answer to 4^{-x}=2^{x^2+2x-8} is x=2(sqrt(3)-1),x=-2(1+sqrt(3))

Solve for x: 4^{-x}=2^{x^2+2x-8}

The solution is x=2(sqrt(3)-1),x=-2(1+sqrt(3))

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4^{- x} = 2^{x^{2} + 2 x - 8}

x = 2 (3 - 1), x = - 2 (1 + 3)

Decimal Notation

x = 1.46410 \dots, x = - 5.46410 \dots

Solution steps

4^{- x} = 2^{x^{2} + 2 x - 8}

Apply exponent rules

- 2 x = x^{2} + 2 x - 8

Solve

- 2 x = x^{2} + 2 x - 8 : x = 2 (3 - 1), x = - 2 (1 + 3)

x = 2 (3 - 1), x = - 2 (1 + 3)

y, x = 2 e^{(3 y)}

2 3^{9} - 2 3^{8} = 22 \cdot 2 3^{x}

62 5^{x} = 25

1 0^{3 x} = 21

24 3^{4 x - 8} = 1

What is the answer to 4^{-x}=2^{x^2+2x-8} ?
The answer to 4^{-x}=2^{x^2+2x-8} is x=2(sqrt(3)-1),x=-2(1+sqrt(3))
Solve for x: 4^{-x}=2^{x^2+2x-8}
The solution is x=2(sqrt(3)-1),x=-2(1+sqrt(3))