What is the answer to 25^x-4*5^x=-4 ?

The answer to 25^x-4*5^x=-4 is x=(ln(2))/(ln(5))

Solve for x: 25^x-4*5^x=-4

The solution is x=(ln(2))/(ln(5))

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2 5^{x} - 4 \cdot 5^{x} = - 4

x = \frac{ln ( 2 )}{ln ( 5 )}

Decimal Notation

x = 0.43067 \dots

Solution steps

2 5^{x} - 4 \cdot 5^{x} = - 4

Apply exponent rules

(5^{x})^{2} - 4 \cdot 5^{x} = - 4

Rewrite the equation with

5^{x} = u

(u)^{2} - 4 u = - 4

Solve

u^{2} - 4 u = - 4 : u = 2

u = 2

Substitute back

u = 5^{x},

solve for

x

Solve

5^{x} = 2 : x = \frac{ln ( 2 )}{ln ( 5 )}

x = \frac{ln ( 2 )}{ln ( 5 )}

4^{x + 2} = 8^{x - 1}

e^{x} + 15 e^{- x} = 8

2^{2 + y} - 2^{1 + y} = 2^{4}

x, - 4^{2 y} = 3^{8 x}

What is the answer to 25^x-4*5^x=-4 ?
The answer to 25^x-4*5^x=-4 is x=(ln(2))/(ln(5))
Solve for x: 25^x-4*5^x=-4
The solution is x=(ln(2))/(ln(5))