What is the answer to solvefor t,45x1.071^t=122 ?

The answer to solvefor t,45x1.071^t=122 is t=(ln(\frac{122)/(45x))}{ln(1.071)}

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solvefor t,45x1.071^t=122

solve for

t, 45 x 1.07 1^{t} = 122

t = \frac{ln ( \frac{122}{45 x} )}{ln ( 1.071 )}

Solution steps

45 x \cdot 1.07 1^{t} = 122

Divide both sides by

45 x

1.07 1^{t} = \frac{122}{45 x}

Apply exponent rules

t ln (1.071) = ln (\frac{122}{45 x})

Solve

t ln (1.071) = ln (\frac{122}{45 x}) : t = \frac{ln ( \frac{122}{45 x} )}{ln ( 1.071 )}

t = \frac{ln ( \frac{122}{45 x} )}{ln ( 1.071 )}

1 6^{x - 3} = 2^{x - 6}

n = 1. 2^{n}

2^{x} = 3.6 \cdot 1 0^{13}

9^{x - 2} = 240 + 9^{x}

5^{x} - 1 = 3

What is the answer to solvefor t,45x1.071^t=122 ?
The answer to solvefor t,45x1.071^t=122 is t=(ln(\frac{122)/(45x))}{ln(1.071)}