What is the answer to 3^{2t-2}=7^{t+2} ?

The answer to 3^{2t-2}=7^{t+2} is t=(2ln(21))/(2ln(3)-ln(7))

Solve for t: 3^{2t-2}=7^{t+2}

The solution is t=(2ln(21))/(2ln(3)-ln(7))

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3^{2 t - 2} = 7^{t + 2}

t = \frac{2 ln ( 21 )}{2 ln ( 3 ) - ln ( 7 )}

Solution steps

3^{2 t - 2} = 7^{t + 2}

Apply exponent rules

(2 t - 2) ln (3) = (t + 2) ln (7)

Solve

(2 t - 2) ln (3) = (t + 2) ln (7) : t = \frac{2 ln ( 21 )}{2 ln ( 3 ) - ln ( 7 )}

t = \frac{2 ln ( 21 )}{2 ln ( 3 ) - ln ( 7 )}

8^{x} = \frac{9}{9 ^{x}}

(\frac{5}{6})^{x} = \frac{6}{5}

5^{x^{2}} = 2 5^{x + 1}

5^{2 x} - 5^{x + 1} + 4 = 0

3^{x^{2}} \cdot 3^{5 x} = 729

What is the answer to 3^{2t-2}=7^{t+2} ?
The answer to 3^{2t-2}=7^{t+2} is t=(2ln(21))/(2ln(3)-ln(7))
Solve for t: 3^{2t-2}=7^{t+2}
The solution is t=(2ln(21))/(2ln(3)-ln(7))