What is the answer to (x-6)^{x^2-5}=(x-6)^{2x+3} ?

The answer to (x-6)^{x^2-5}=(x-6)^{2x+3} is x=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-6)^{x^2-5}=(x-6)^{2x+3}

(x - 6)^{x^{2} - 5} = (x - 6)^{2 x + 3}

x = 7

Solution steps

(x - 6)^{x^{2} - 5} = (x - 6)^{2 x + 3}

Apply exponent rules

(x^{2} - 5) ln (x - 6) = (2 x + 3) ln (x - 6)

Solve

(x^{2} - 5) ln (x - 6) = (2 x + 3) ln (x - 6) : x = 7

x = 7

2^{3 x} = 8^{2 x + 1}

(\frac{1}{100})^{2 x} = 0.0001

3^{2 x - 3} = \frac{2 7 ^{x + 1}}{2}

e^{- 4 x} - 4 x e^{- 4 x} = 0

1 0^{a} = 92

What is the answer to (x-6)^{x^2-5}=(x-6)^{2x+3} ?
The answer to (x-6)^{x^2-5}=(x-6)^{2x+3} is x=7
Solve for x: (x-6)^{x^2-5}=(x-6)^{2x+3}
The solution is x=7