What is the answer to 2*5^{x+1}+5^{x-1}=51 ?

The answer to 2*5^{x+1}+5^{x-1}=51 is x=1

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2*5^{x+1}+5^{x-1}=51

2 \cdot 5^{x + 1} + 5^{x - 1} = 51

x = 1

Solution steps

2 \cdot 5^{x + 1} + 5^{x - 1} = 51

Factor

2 \cdot 5^{x + 1} + 5^{x - 1} : 51 \cdot 5^{x - 1}

51 \cdot 5^{x - 1} = 51

Divide both sides by

51

5^{x - 1} = 1

Apply exponent rules

(x - 1) ln (5) = ln (1)

Solve

(x - 1) ln (5) = ln (1) : x = 1

x = 1

(\frac{1}{2})^{x + 1} = 8

x, r - 4 s + 4 t = e^{2 x + y}

e^{x + 8} = 8^{\frac{x}{2}}

x, w = z e^{x yz}

3 6^{x - 3} + 10 = 16

What is the answer to 2*5^{x+1}+5^{x-1}=51 ?
The answer to 2*5^{x+1}+5^{x-1}=51 is x=1
Solve for x: 2*5^{x+1}+5^{x-1}=51
The solution is x=1