What is the answer to 61*2^x=99 ?

The answer to 61*2^x=99 is x=(ln(99/61))/(ln(2))

Solve for x: 61*2^x=99

The solution is x=(ln(99/61))/(ln(2))

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61 \cdot 2^{x} = 99

x = \frac{ln ( \frac{99}{61} )}{ln ( 2 )}

Solution steps

61 \cdot 2^{x} = 99

Divide both sides by

61

2^{x} = \frac{99}{61}

Apply exponent rules

x ln (2) = ln (\frac{99}{61})

Solve

x ln (2) = ln (\frac{99}{61}) : x = \frac{ln ( \frac{99}{61} )}{ln ( 2 )}

x = \frac{ln ( \frac{99}{61} )}{ln ( 2 )}

\frac{6}{( 2 ^{x} )} = 45

60 = 5 (1 + \frac{0.025}{12})^{x}

2 5^{x} + 2 5^{x} = \frac{2}{5}

25 6^{4 x} = 6 4^{x + 3}

3^{x} = - \frac{2}{3}

What is the answer to 61*2^x=99 ?
The answer to 61*2^x=99 is x=(ln(99/61))/(ln(2))
Solve for x: 61*2^x=99
The solution is x=(ln(99/61))/(ln(2))