What is the answer to (4^{x-1})/(2^{x+2)}=256 ?

The answer to (4^{x-1})/(2^{x+2)}=256 is x=12

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(4^{x-1})/(2^{x+2)}=256

\frac{4 ^{x - 1}}{2 ^{x + 2}} = 256

x = 12

Solution steps

\frac{4 ^{x - 1}}{2 ^{x + 2}} = 256

Apply exponent rules

2 (x - 1) - x - 2 = 8

Solve

2 (x - 1) - x - 2 = 8 : x = 12

x = 12

Verify Solutions:

x = 12

True

The solution is

x = 12

2 7^{- x - 1} = 81

e^{- \frac{1}{2} x^{2}} = 0

8 1^{x} = 3^{4 x}

(1.07)^{x} = 2

5 + e^{q} = - \frac{q}{2} + 2

What is the answer to (4^{x-1})/(2^{x+2)}=256 ?
The answer to (4^{x-1})/(2^{x+2)}=256 is x=12
Solve for x: (4^{x-1})/(2^{x+2)}=256
The solution is x=12