What is the answer to 3*4^x=2*12^x ?

The answer to 3*4^x=2*12^x is x=(ln(3)-ln(2))/(ln(3))

Solve for x: 3*4^x=2*12^x

The solution is x=(ln(3)-ln(2))/(ln(3))

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3 \cdot 4^{x} = 2 \cdot 1 2^{x}

x = \frac{ln ( 3 ) - ln ( 2 )}{ln ( 3 )}

Decimal Notation

x = 0.36907 \dots

Solution steps

3 \cdot 4^{x} = 2 \cdot 1 2^{x}

Apply exponent rules

ln (3) + x ln (4) = ln (2) + x ln (12)

Solve

ln (3) + x ln (4) = ln (2) + x ln (12) : x = \frac{ln ( 3 ) - ln ( 2 )}{ln ( 3 )}

x = \frac{ln ( 3 ) - ln ( 2 )}{ln ( 3 )}

2^{(- 3 x)} \cdot 4^{(2 x - 2)} = 16

2^{2 x} = 2^{x} + 12

5^{2 x - 1} = 5^{3}

e^{t} = 2

1 2^{x + 5} = 300

What is the answer to 3*4^x=2*12^x ?
The answer to 3*4^x=2*12^x is x=(ln(3)-ln(2))/(ln(3))
Solve for x: 3*4^x=2*12^x
The solution is x=(ln(3)-ln(2))/(ln(3))