What is the answer to 1/(3e^{2-3x)+3}=7 ?

The answer to 1/(3e^{2-3x)+3}=7 is No Solution for x\in\mathbb{R}

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1/(3e^{2-3x)+3}=7

\frac{1}{3 e ^{2 - 3 x} + 3} = 7

No Solution for x \in R

Solution steps

\frac{1}{3 e ^{2 - 3 x} + 3} = 7

Multiply both sides by

3 e^{2 - 3 x} + 3

\frac{1}{3 e ^{2 - 3 x} + 3} (3 e^{2 - 3 x} + 3) = 7 (3 e^{2 - 3 x} + 3)

Simplify

1 = 7 (3 e^{2 - 3 x} + 3)

Switch sides

7 (3 e^{2 - 3 x} + 3) = 1

Divide both sides by

7

3 e^{2 - 3 x} + 3 = \frac{1}{7}

Move

3

to the right side

3 e^{2 - 3 x} = - \frac{20}{7}

Divide both sides by

3

e^{2 - 3 x} = - \frac{20}{21}

a^{f (x)}

cannot be zero or negative for

x \in R

No Solution for x \in R

7^{3 x^{2}} = 4 9^{6 x + 2}

9^{x} - 4 = 3^{x + 1}

e^{x} + 6 \cdot e^{- x} = 5

100 - 98 y + 980 (1 - e^{- 0.1 y}) = 0

4 e^{2 x} = 0

What is the answer to 1/(3e^{2-3x)+3}=7 ?
The answer to 1/(3e^{2-3x)+3}=7 is No Solution for x\in\mathbb{R}