What is the answer to 9*2^{x-1}=2*3^x ?

The answer to 9*2^{x-1}=2*3^x is x=(2ln(3)-2ln(2))/(ln(3)-ln(2))

Solve for x: 9*2^{x-1}=2*3^x

The solution is x=(2ln(3)-2ln(2))/(ln(3)-ln(2))

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9 \cdot 2^{x - 1} = 2 \cdot 3^{x}

x = \frac{2 ln ( 3 ) - 2 ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

Decimal Notation

x = 2

Solution steps

9 \cdot 2^{x - 1} = 2 \cdot 3^{x}

Apply exponent rules

ln (9) + (x - 1) ln (2) = ln (2) + x ln (3)

Solve

ln (9) + (x - 1) ln (2) = ln (2) + x ln (3) : x = \frac{2 ln ( 3 ) - 2 ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

x = \frac{2 ln ( 3 ) - 2 ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

2^{(x^{2} - 10 x + 25)} - 5 = 11

3^{x + 1} + 5 = 2^{5}

5 e^{x + 7} = 14

e^{\frac{3 x}{4}} = 0

What is the answer to 9*2^{x-1}=2*3^x ?
The answer to 9*2^{x-1}=2*3^x is x=(2ln(3)-2ln(2))/(ln(3)-ln(2))
Solve for x: 9*2^{x-1}=2*3^x
The solution is x=(2ln(3)-2ln(2))/(ln(3)-ln(2))