What is the answer to 3^{(x+2)}=7 ?

The answer to 3^{(x+2)}=7 is x=(ln(7))/(ln(3))-2

Solve for x: 3^{(x+2)}=7

The solution is x=(ln(7))/(ln(3))-2

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3^{(x + 2)} = 7

x = \frac{ln ( 7 )}{ln ( 3 )} - 2

Decimal Notation

x = - 0.22875 \dots

Solution steps

3^{(x + 2)} = 7

Apply exponent rules

(x + 2) ln (3) = ln (7)

Solve

(x + 2) ln (3) = ln (7) : x = \frac{ln ( 7 )}{ln ( 3 )} - 2

x = \frac{ln ( 7 )}{ln ( 3 )} - 2

2^{3 x + 1} = 2^{3}

7^{x + 2} = 410

2^{3 x - 6} = 2^{x - 3}

1536 = 3 (2)^{n - 1}

3^{- 5 x} = 81

What is the answer to 3^{(x+2)}=7 ?
The answer to 3^{(x+2)}=7 is x=(ln(7))/(ln(3))-2
Solve for x: 3^{(x+2)}=7
The solution is x=(ln(7))/(ln(3))-2