What is the answer to 2^{2x}-5(2^x)=-4 ?

The answer to 2^{2x}-5(2^x)=-4 is x=2,x=0

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2^{2x}-5(2^x)=-4

2^{2 x} - 5 (2^{x}) = - 4

x = 2, x = 0

Solution steps

2^{2 x} - 5 (2^{x}) = - 4

Apply exponent rules

(2^{x})^{2} - 5 \cdot 2^{x} = - 4

Rewrite the equation with

2^{x} = u

(u)^{2} - 5 u = - 4

Solve

u^{2} - 5 u = - 4 : u = 4, u = 1

u = 4, u = 1

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 4 : x = 2

Solve

2^{x} = 1 : x = 0

x = 2, x = 0

4.7 = 3 (1 + 0.23)^{n}

x, - y = e^{3 x}

16 = 16 e^{34 x} + 5

\frac{2}{3} = (\frac{2}{3})^{x}

m, a^{m} \cdot a^{n} = a

What is the answer to 2^{2x}-5(2^x)=-4 ?
The answer to 2^{2x}-5(2^x)=-4 is x=2,x=0
Solve for x: 2^{2x}-5(2^x)=-4
The solution is x=2,x=0