What is the answer to 3^{-5x+2}=(1/9)^{x+2} ?

The answer to 3^{-5x+2}=(1/9)^{x+2} is x=2

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3^{-5x+2}=(1/9)^{x+2}

3^{- 5 x + 2} = (\frac{1}{9})^{x + 2}

x = 2

Solution steps

3^{- 5 x + 2} = (\frac{1}{9})^{x + 2}

Apply exponent rules

- 5 x + 2 = - 2 (x + 2)

Solve

- 5 x + 2 = - 2 (x + 2) : x = 2

x = 2

2 + x = 2^{x}

8 \cdot 2^{3 x} - 32 = 0

3^{y} = 81

5 (7^{(2 x - 1)}) = 7 (5^{(x + 2)})

What is the answer to 3^{-5x+2}=(1/9)^{x+2} ?
The answer to 3^{-5x+2}=(1/9)^{x+2} is x=2
Solve for x: 3^{-5x+2}=(1/9)^{x+2}
The solution is x=2