What is the answer to 2=1.02^x ?

The answer to 2=1.02^x is x=(ln(2))/(ln(1.02))

Solve for x: 2=1.02^x

The solution is x=(ln(2))/(ln(1.02))

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2 = 1.0 2^{x}

x = \frac{ln ( 2 )}{ln ( 1.02 )}

Solution steps

2 = 1.0 2^{x}

Apply exponent rules

ln (2) = x ln (1.02)

Solve

ln (2) = x ln (1.02) : x = \frac{ln ( 2 )}{ln ( 1.02 )}

x = \frac{ln ( 2 )}{ln ( 1.02 )}

2 5^{x} \cdot 5^{x^{2}} = 62 5^{2}

2^{4 x} = 256

y, (6 x)^{y} = 3 d + 4

- 6^{2 x} + 5 = - 18.5

8^{6 x - 5} 2^{3 x + 1} = 2^{8 x + 9}