What is the answer to 12000=1520*1.04^x ?

The answer to 12000=1520*1.04^x is x=(ln(150/19))/(ln(1.04))

Solve for x: 12000=1520*1.04^x

The solution is x=(ln(150/19))/(ln(1.04))

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12000 = 1520 \cdot 1.0 4^{x}

x = \frac{ln ( \frac{150}{19} )}{ln ( 1.04 )}

Solution steps

12000 = 1520 \cdot 1.0 4^{x}

Switch sides

1520 \cdot 1.0 4^{x} = 12000

Divide both sides by

1520

1.0 4^{x} = \frac{150}{19}

Apply exponent rules

x ln (1.04) = ln (\frac{150}{19})

Solve

x ln (1.04) = ln (\frac{150}{19}) : x = \frac{ln ( \frac{150}{19} )}{ln ( 1.04 )}

x = \frac{ln ( \frac{150}{19} )}{ln ( 1.04 )}

3^{2 x + 1} = 5 (3^{x}) + 2

1 = e^{c}

e^{\frac{2}{3} t} = e^{10}

2 5^{9 x - 8} = 120

4^{x + 3} = 1 6^{x - 5}

What is the answer to 12000=1520*1.04^x ?
The answer to 12000=1520*1.04^x is x=(ln(150/19))/(ln(1.04))
Solve for x: 12000=1520*1.04^x
The solution is x=(ln(150/19))/(ln(1.04))