What is the answer to solvefor x,0=3^{-x}-7 ?

The answer to solvefor x,0=3^{-x}-7 is x=-(ln(7))/(ln(3))

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solvefor x,0=3^{-x}-7

solve for

x, 0 = 3^{- x} - 7

x = - \frac{ln ( 7 )}{ln ( 3 )}

Solution steps

0 = 3^{- x} - 7

Add

7

to both sides

0 + 7 = 3^{- x} - 7 + 7

Simplify

7 = 3^{- x}

Apply exponent rules

ln (7) = - x ln (3)

Solve

ln (7) = - x ln (3) : x = - \frac{ln ( 7 )}{ln ( 3 )}

x = - \frac{ln ( 7 )}{ln ( 3 )}

5^{x} = 9 \cdot 4^{x}

4^{5 p - 1} = 8^{p - 2}

\frac{1}{2} (3)^{x} = \frac{9}{2}

8 1^{2^{x + 7}} = 3^{8^{x - 13}}

x, e^{2 x} - 11 e^{x} + 30 = 0

What is the answer to solvefor x,0=3^{-x}-7 ?
The answer to solvefor x,0=3^{-x}-7 is x=-(ln(7))/(ln(3))