What is the answer to 25^{2x+1}-1=143 ?

The answer to 25^{2x+1}-1=143 is x=(ln(12)-ln(5))/(2ln(5))

Solve for x: 25^{2x+1}-1=143

The solution is x=(ln(12)-ln(5))/(2ln(5))

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2 5^{2 x + 1} - 1 = 143

x = \frac{ln ( 12 ) - ln ( 5 )}{2 ln ( 5 )}

Decimal Notation

x = 0.27197 \dots

Solution steps

2 5^{2 x + 1} - 1 = 143

Move

1

to the right side

2 5^{2 x + 1} = 144

Apply exponent rules

(2 x + 1) ln (25) = ln (144)

Solve

(2 x + 1) ln (25) = ln (144) : x = \frac{ln ( 12 ) - ln ( 5 )}{2 ln ( 5 )}

x = \frac{ln ( 12 ) - ln ( 5 )}{2 ln ( 5 )}

11 (1 + e^{- x})^{- 1} = 3

1536 = 6 (2)^{n - 1}

5^{2 x + 4} - 2 5^{x - 1} = 78120

10000 = 2^{x}

1 0^{3 x} = 10000

What is the answer to 25^{2x+1}-1=143 ?
The answer to 25^{2x+1}-1=143 is x=(ln(12)-ln(5))/(2ln(5))
Solve for x: 25^{2x+1}-1=143
The solution is x=(ln(12)-ln(5))/(2ln(5))