What is the answer to log_{10}(3^x)=81 ?

The answer to log_{10}(3^x)=81 is x=(81ln(10))/(ln(3))

Solve for x: log_{10}(3^x)=81

The solution is x=(81ln(10))/(ln(3))

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lo g_{10} (3^{x}) = 81

x = \frac{81 ln ( 10 )}{ln ( 3 )}

Solution steps

lo g_{10} (3^{x}) = 81

Rewrite the equation with

3^{x} = u

lo g_{10} (u) = 81

Solve

lo g_{10} (u) = 81 : u = 1 0^{81}

u = 1 0^{81}

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 1 0^{81} : x = \frac{81 ln ( 10 )}{ln ( 3 )}

x = \frac{81 ln ( 10 )}{ln ( 3 )}

1 5^{- 3 y} = 8

1 5^{- 3 y} = 9

y, z = x e^{x^{2} y}

lo g_{10} (10 0^{x}) = 70

(- 7)^{x - 2} = 16.807

What is the answer to log_{10}(3^x)=81 ?
The answer to log_{10}(3^x)=81 is x=(81ln(10))/(ln(3))
Solve for x: log_{10}(3^x)=81
The solution is x=(81ln(10))/(ln(3))