What is the answer to 3^{x+5}=7 ?

The answer to 3^{x+5}=7 is x=(ln(7))/(ln(3))-5

Solve for x: 3^{x+5}=7

The solution is x=(ln(7))/(ln(3))-5

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3^{x + 5} = 7

x = \frac{ln ( 7 )}{ln ( 3 )} - 5

Solution steps

3^{x + 5} = 7

Apply exponent rules

(x + 5) ln (3) = ln (7)

Solve

(x + 5) ln (3) = ln (7) : x = \frac{ln ( 7 )}{ln ( 3 )} - 5

x = \frac{ln ( 7 )}{ln ( 3 )} - 5

5^{x} + 5^{x + 1} + 5^{x + 2} = 155

e^{x} + e^{- x} = 7.4533

x^{x} = 625

t, a = p e^{r t}

2^{3^{x - 5}} = 8^{9^{x + 4}}

What is the answer to 3^{x+5}=7 ?
The answer to 3^{x+5}=7 is x=(ln(7))/(ln(3))-5
Solve for x: 3^{x+5}=7
The solution is x=(ln(7))/(ln(3))-5