What is the answer to 16^{x+2}=64^{2x-5} ?

The answer to 16^{x+2}=64^{2x-5} is x= 19/4

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16^{x+2}=64^{2x-5}

1 6^{x + 2} = 6 4^{2 x - 5}

x = \frac{19}{4}

Decimal Notation

x = 4.75

Solution steps

1 6^{x + 2} = 6 4^{2 x - 5}

Apply exponent rules

2 (x + 2) = 3 (2 x - 5)

Solve

2 (x + 2) = 3 (2 x - 5) : x = \frac{19}{4}

x = \frac{19}{4}

2^{x} = 3^{2 x}

5^{11 x + 23} = 12 5^{7 x}

1 0^{l o g_{5} (x)} = 5

e^{- 2 x} - 2 x e^{- 2 x} = 0

(1 + x)^{\frac{72}{100 x}} = 2

What is the answer to 16^{x+2}=64^{2x-5} ?
The answer to 16^{x+2}=64^{2x-5} is x= 19/4
Solve for x: 16^{x+2}=64^{2x-5}
The solution is x= 19/4