What is the answer to 16^{2x+1}=4^{1-x} ?

The answer to 16^{2x+1}=4^{1-x} is x=-1/5

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16^{2x+1}=4^{1-x}

1 6^{2 x + 1} = 4^{1 - x}

x = - \frac{1}{5}

Solution steps

1 6^{2 x + 1} = 4^{1 - x}

Apply exponent rules

2 (2 x + 1) = 1 - x

Solve

2 (2 x + 1) = 1 - x : x = - \frac{1}{5}

x = - \frac{1}{5}

e^{a^{2} + 2 a} = e^{3 a}

t = 0.05 e^{0.086664 \cdot t}

2 \cdot 2^{2 x} = 17 \cdot 2^{x} - 8

2^{3 - 3 x} = 64

What is the answer to 16^{2x+1}=4^{1-x} ?
The answer to 16^{2x+1}=4^{1-x} is x=-1/5
Solve for x: 16^{2x+1}=4^{1-x}
The solution is x=-1/5