What is the answer to -2^{x+1}+5*2^x=28 ?

The answer to -2^{x+1}+5*2^x=28 is x=(ln(28/3))/(ln(2))

Solve for x: -2^{x+1}+5*2^x=28

The solution is x=(ln(28/3))/(ln(2))

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- 2^{x + 1} + 5 \cdot 2^{x} = 28

x = \frac{ln ( \frac{28}{3} )}{ln ( 2 )}

Solution steps

- 2^{x + 1} + 5 \cdot 2^{x} = 28

Factor

- 2^{x + 1} + 5 \cdot 2^{x} : 3 \cdot 2^{x}

3 \cdot 2^{x} = 28

Divide both sides by

3

2^{x} = \frac{28}{3}

Apply exponent rules

x ln (2) = ln (\frac{28}{3})

Solve

x ln (2) = ln (\frac{28}{3}) : x = \frac{ln ( \frac{28}{3} )}{ln ( 2 )}

x = \frac{ln ( \frac{28}{3} )}{ln ( 2 )}

1 0^{a} = 1000000

2^{2 x + 2} = 3 - 2^{x}

82 = 2^{x}

4^{x - 2} = 13

4 = e^{2 x}

What is the answer to -2^{x+1}+5*2^x=28 ?
The answer to -2^{x+1}+5*2^x=28 is x=(ln(28/3))/(ln(2))
Solve for x: -2^{x+1}+5*2^x=28
The solution is x=(ln(28/3))/(ln(2))