What is the answer to 2^x=3^{x+3} ?

The answer to 2^x=3^{x+3} is x=(3ln(3))/(ln(2)-ln(3))

Solve for x: 2^x=3^{x+3}

The solution is x=(3ln(3))/(ln(2)-ln(3))

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2^{x} = 3^{x + 3}

x = \frac{3 ln ( 3 )}{ln ( 2 ) - ln ( 3 )}

Solution steps

2^{x} = 3^{x + 3}

Apply exponent rules

x ln (2) = (x + 3) ln (3)

Solve

x ln (2) = (x + 3) ln (3) : x = \frac{3 ln ( 3 )}{ln ( 2 ) - ln ( 3 )}

x = \frac{3 ln ( 3 )}{ln ( 2 ) - ln ( 3 )}

\frac{93}{151} = e^{- 12 k}

2^{x} = 20000000

8^{9 x + 8} = 3

3^{x + 1} = \frac{1}{27}

\frac{1}{e ^{y}} = e^{- y}

What is the answer to 2^x=3^{x+3} ?
The answer to 2^x=3^{x+3} is x=(3ln(3))/(ln(2)-ln(3))
Solve for x: 2^x=3^{x+3}
The solution is x=(3ln(3))/(ln(2)-ln(3))