What is the answer to 5(2^{3x-2})=9^x ?

The answer to 5(2^{3x-2})=9^x is x=(ln(5)-2ln(2))/(2ln(3)-3ln(2))

Solve for x: 5(2^{3x-2})=9^x

The solution is x=(ln(5)-2ln(2))/(2ln(3)-3ln(2))

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5 (2^{3 x - 2}) = 9^{x}

x = \frac{ln ( 5 ) - 2 ln ( 2 )}{2 ln ( 3 ) - 3 ln ( 2 )}

Decimal Notation

x = 1.89453 \dots

Solution steps

5 (2^{3 x - 2}) = 9^{x}

Apply exponent rules

ln (5) + (3 x - 2) ln (2) = x ln (9)

Solve

ln (5) + (3 x - 2) ln (2) = x ln (9) : x = \frac{ln ( 5 ) - 2 ln ( 2 )}{2 ln ( 3 ) - 3 ln ( 2 )}

x = \frac{ln ( 5 ) - 2 ln ( 2 )}{2 ln ( 3 ) - 3 ln ( 2 )}

1 6^{9 x - 6} = (2^{4})^{6 + 7 x}

x, e^{e^{x}} = 2

8 = e^{t}

2^{t} = 43

91 = 3 1^{x}

What is the answer to 5(2^{3x-2})=9^x ?
The answer to 5(2^{3x-2})=9^x is x=(ln(5)-2ln(2))/(2ln(3)-3ln(2))
Solve for x: 5(2^{3x-2})=9^x
The solution is x=(ln(5)-2ln(2))/(2ln(3)-3ln(2))