What is the answer to 3^b=17 ?

The answer to 3^b=17 is b=(ln(17))/(ln(3))

The solution is b=(ln(17))/(ln(3))

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3^b=17

3^{b} = 17

b = \frac{ln ( 17 )}{ln ( 3 )}

Decimal Notation

b = 2.57890 \dots

Solution steps

3^{b} = 17

Apply exponent rules

b ln (3) = ln (17)

Solve

b ln (3) = ln (17) : b = \frac{ln ( 17 )}{ln ( 3 )}

b = \frac{ln ( 17 )}{ln ( 3 )}

(23)^{3 x - 4} = 20736

(e^{x} + 1)^{3} e^{- x} d y = 0

2 \cdot 4^{x} - 5 \cdot 2^{x} + 2 = 0

0 = 10 (1 - e^{(- 0.5 t)})

0. 1^{X} = 0.001