What is the answer to 5^{x-1}=3^{x+1} ?

The answer to 5^{x-1}=3^{x+1} is x=(ln(15))/(ln(5)-ln(3))

Solve for x: 5^{x-1}=3^{x+1}

The solution is x=(ln(15))/(ln(5)-ln(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5^{x - 1} = 3^{x + 1}

x = \frac{ln ( 15 )}{ln ( 5 ) - ln ( 3 )}

Decimal Notation

x = 5.30132 \dots

Solution steps

5^{x - 1} = 3^{x + 1}

Apply exponent rules

(x - 1) ln (5) = (x + 1) ln (3)

Solve

(x - 1) ln (5) = (x + 1) ln (3) : x = \frac{ln ( 15 )}{ln ( 5 ) - ln ( 3 )}

x = \frac{ln ( 15 )}{ln ( 5 ) - ln ( 3 )}

4^{4 x} = 8

x, c = y a^{x}

n, y^{n} = 0

2^{x - 3} = 2^{7}

What is the answer to 5^{x-1}=3^{x+1} ?
The answer to 5^{x-1}=3^{x+1} is x=(ln(15))/(ln(5)-ln(3))
Solve for x: 5^{x-1}=3^{x+1}
The solution is x=(ln(15))/(ln(5)-ln(3))