What are the solutions to the equation 256-16t^2=0 ?

The solutions to the equation 256-16t^2=0 are t=4,t=-4

Find the zeros of 256-16t^2=0

The zeros of 256-16t^2=0 are t=4,t=-4

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256 - 16 t^{2} = 0

t = 4, t = - 4

Solution steps

256 - 16 t^{2} = 0

Move

256

to the right side

- 16 t^{2} = - 256

Divide both sides by

- 16

t^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 16, t = - 16

16 = 4

- 16 = - 4

t = 4, t = - 4

3 y + \frac{2}{5} = - \frac{1}{5}

z^{2} = 18 - 7 z

\frac{3}{2} \cdot 8

\frac{12 !}{( 12 - 3 ) !}

2 \cdot 32

What are the solutions to the equation 256-16t^2=0 ?
The solutions to the equation 256-16t^2=0 are t=4,t=-4
Find the zeros of 256-16t^2=0
The zeros of 256-16t^2=0 are t=4,t=-4