What is the answer to 2^{n-1}=360000 ?

The answer to 2^{n-1}=360000 is n=(2ln(600))/(ln(2))+1

Solve for n: 2^{n-1}=360000

The solution is n=(2ln(600))/(ln(2))+1

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2^{n - 1} = 360000

n = \frac{2 ln ( 600 )}{ln ( 2 )} + 1

Decimal Notation

n = 19.45763 \dots

Solution steps

2^{n - 1} = 360000

Apply exponent rules

(n - 1) ln (2) = ln (360000)

Solve

(n - 1) ln (2) = ln (360000) : n = \frac{2 ln ( 600 )}{ln ( 2 )} + 1

n = \frac{2 ln ( 600 )}{ln ( 2 )} + 1

6 \cdot e^{x} = 25

e^{5 - 4 x} = 6

e^{5 - 4 x} = 7

500 = 2000 \cdot (2^{- 0.1 x})

5^{x + 1} + 5^{x - 2} + 5^{x - 1} = 131

What is the answer to 2^{n-1}=360000 ?
The answer to 2^{n-1}=360000 is n=(2ln(600))/(ln(2))+1
Solve for n: 2^{n-1}=360000
The solution is n=(2ln(600))/(ln(2))+1