What is the answer to 2^{x-1}=5^{1-2x} ?

The answer to 2^{x-1}=5^{1-2x} is x=(ln(10))/(ln(50))

Solve for x: 2^{x-1}=5^{1-2x}

The solution is x=(ln(10))/(ln(50))

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2^{x - 1} = 5^{1 - 2 x}

x = \frac{ln ( 10 )}{ln ( 50 )}

Decimal Notation

x = 0.58859 \dots

Solution steps

2^{x - 1} = 5^{1 - 2 x}

Apply exponent rules

(x - 1) ln (2) = (1 - 2 x) ln (5)

Solve

(x - 1) ln (2) = (1 - 2 x) ln (5) : x = \frac{ln ( 10 )}{ln ( 50 )}

x = \frac{ln ( 10 )}{ln ( 50 )}

8 = 4^{x - 2}

y, x^{y} = y^{x}

k, - 2 e^{- 4 k} = 1

2^{x + 5} = 2^{2 x + 1}

5^{x + 1} - 5^{x - 1} = 24

What is the answer to 2^{x-1}=5^{1-2x} ?
The answer to 2^{x-1}=5^{1-2x} is x=(ln(10))/(ln(50))
Solve for x: 2^{x-1}=5^{1-2x}
The solution is x=(ln(10))/(ln(50))