What is the answer to solvefor t,N=ae^{-0.21*t} ?

The answer to solvefor t,N=ae^{-0.21*t} is t=-(ln(N/a))/(0.21)

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solvefor t,N=ae^{-0.21*t}

solve for

t, N = a e^{- 0.21 \cdot t}

t = - \frac{ln ( \frac{N}{a} )}{0.21}

Solution steps

N = a e^{- 0.21 t}

Switch sides

a e^{- 0.21 t} = N

Divide both sides by

a

e^{- 0.21 t} = \frac{N}{a}

Apply exponent rules

- 0.21 t = ln (\frac{N}{a})

Solve

- 0.21 t = ln (\frac{N}{a}) : t = - \frac{ln ( \frac{N}{a} )}{0.21}

t = - \frac{ln ( \frac{N}{a} )}{0.21}

21 6^{- 3 x} = 36

5^{6 - x} = 1

50 e^{- 0.12 t} = 10

6^{x} = e^{x + 8}

2 (3)^{2 x + 1} = 5^{x - 3}

What is the answer to solvefor t,N=ae^{-0.21*t} ?
The answer to solvefor t,N=ae^{-0.21*t} is t=-(ln(N/a))/(0.21)