What is the answer to 9^x=(1/9)^{x+3} ?

The answer to 9^x=(1/9)^{x+3} is x=-3/2

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9^x=(1/9)^{x+3}

9^{x} = (\frac{1}{9})^{x + 3}

x = - \frac{3}{2}

Decimal Notation

x = - 1.5

Solution steps

9^{x} = (\frac{1}{9})^{x + 3}

Apply exponent rules

x = - (x + 3)

Solve

x = - (x + 3) : x = - \frac{3}{2}

x = - \frac{3}{2}

(\frac{6}{5})^{n} = 16

4^{2 x - 3} = 1

z, e^{2 x + 2 y + z} = c

8^{x - 2} = 1 6^{5 x + 4}

x = 2^{\frac{x}{8}}