What is the answer to 0.8=-e^{(-2t-(-2))/7}+1 ?

The answer to 0.8=-e^{(-2t-(-2))/7}+1 is t=(-7ln(0.2)+2)/2

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0.8=-e^{(-2t-(-2))/7}+1

0.8 = - e^{\frac{- 2 t - ( - 2 )}{7}} + 1

t = \frac{- 7 ln ( 0.2 ) + 2}{2}

Decimal Notation

t = 6.63303 \dots

Solution steps

0.8 = - e^{\frac{- 2 t - ( - 2 )}{7}} + 1

Move

e^{\frac{- 2 t - ( - 2 )}{7}}

to the left side

0.8 + e^{\frac{- 2 t - ( - 2 )}{7}} = 1

Move

0.8

to the right side

e^{\frac{- 2 t - ( - 2 )}{7}} = 0.2

Apply exponent rules

\frac{- 2 t - ( - 2 )}{7} = ln (0.2)

Solve

\frac{- 2 t - ( - 2 )}{7} = ln (0.2) : t = \frac{- 7 ln ( 0.2 ) + 2}{2}

t = \frac{- 7 ln ( 0.2 ) + 2}{2}

6 = 2^{4 x - 3}

z, e^{2 x + 2 y + z} = 1

x, 4^{2 x^{2} + 2 x} = 8

12 5^{r} = 5

What is the answer to 0.8=-e^{(-2t-(-2))/7}+1 ?
The answer to 0.8=-e^{(-2t-(-2))/7}+1 is t=(-7ln(0.2)+2)/2