What is the answer to 3^{(2x+1)}=7^{(x+1)} ?

The answer to 3^{(2x+1)}=7^{(x+1)} is x=(ln(7)-ln(3))/(2ln(3)-ln(7))

Solve for x: 3^{(2x+1)}=7^{(x+1)}

The solution is x=(ln(7)-ln(3))/(2ln(3)-ln(7))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{(2 x + 1)} = 7^{(x + 1)}

x = \frac{ln ( 7 ) - ln ( 3 )}{2 ln ( 3 ) - ln ( 7 )}

Decimal Notation

x = 3.37146 \dots

Solution steps

3^{(2 x + 1)} = 7^{(x + 1)}

Apply exponent rules

(2 x + 1) ln (3) = (x + 1) ln (7)

Solve

(2 x + 1) ln (3) = (x + 1) ln (7) : x = \frac{ln ( 7 ) - ln ( 3 )}{2 ln ( 3 ) - ln ( 7 )}

x = \frac{ln ( 7 ) - ln ( 3 )}{2 ln ( 3 ) - ln ( 7 )}

\frac{1}{e ^{- x}} = e^{x}

x 5^{2 x + 3} = \frac{1}{25}

8200 = 6400 \cdot (1.054)^{4 x}

e^{4 x} - 7 e^{2 x} + 12 = 0

2^{- 3 d + 1} = 2^{- 2 d}

What is the answer to 3^{(2x+1)}=7^{(x+1)} ?
The answer to 3^{(2x+1)}=7^{(x+1)} is x=(ln(7)-ln(3))/(2ln(3)-ln(7))
Solve for x: 3^{(2x+1)}=7^{(x+1)}
The solution is x=(ln(7)-ln(3))/(2ln(3)-ln(7))