What is the answer to 1/8*2^{2x}+8=9 ?

The answer to 1/8*2^{2x}+8=9 is x= 3/2

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1/8*2^{2x}+8=9

\frac{1}{8} \cdot 2^{2 x} + 8 = 9

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

\frac{1}{8} \cdot 2^{2 x} + 8 = 9

Move

8

to the right side

\frac{1}{8} \cdot 2^{2 x} = 1

Multiply both sides by

8

2^{2 x} = 8

Apply exponent rules

2 x = 3

Solve

2 x = 3 : x = \frac{3}{2}

x = \frac{3}{2}

t, 0.2 = e^{- k t}

1 + 3^{z^{2} - 2} = 5

3^{2 x + 1} + 9 = 28 \cdot 3^{x}

15 = 6 e^{0.07 k}

2^{x - 10} = x^{3}