What is the answer to 33^X=2 ?

The answer to 33^X=2 is X=(ln(2))/(ln(33))

The solution is X=(ln(2))/(ln(33))

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33^X=2

3 3^{X} = 2

X = \frac{ln ( 2 )}{ln ( 33 )}

Decimal Notation

X = 0.19823 \dots

Solution steps

3 3^{X} = 2

Apply exponent rules

X ln (33) = ln (2)

Solve

X ln (33) = ln (2) : X = \frac{ln ( 2 )}{ln ( 33 )}

X = \frac{ln ( 2 )}{ln ( 33 )}

8^{x} = 2 + 7

9^{n} = 729

4 e^{x} - \frac{5}{e ^{x}} + e^{x} = 0

9^{x + 2} = 2 7^{x - 1}

2^{3 x + 9} = 4^{x + 3}