What is the answer to 4*3^{7x}=9*2^{7x} ?

The answer to 4*3^{7x}=9*2^{7x} is x=(2ln(3)-2ln(2))/(7(-ln(2)+ln(3)))

Solve for x: 4*3^{7x}=9*2^{7x}

The solution is x=(2ln(3)-2ln(2))/(7(-ln(2)+ln(3)))

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4 \cdot 3^{7 x} = 9 \cdot 2^{7 x}

x = \frac{2 ln ( 3 ) - 2 ln ( 2 )}{7 ( - ln ( 2 ) + ln ( 3 ) )}

Decimal Notation

x = 0.28571 \dots

Solution steps

4 \cdot 3^{7 x} = 9 \cdot 2^{7 x}

Apply exponent rules

ln (4) + 7 x ln (3) = ln (9) + 7 x ln (2)

Solve

ln (4) + 7 x ln (3) = ln (9) + 7 x ln (2) : x = \frac{2 ln ( 3 ) - 2 ln ( 2 )}{7 ( - ln ( 2 ) + ln ( 3 ) )}

x = \frac{2 ln ( 3 ) - 2 ln ( 2 )}{7 ( - ln ( 2 ) + ln ( 3 ) )}

3^{3 μ} = \frac{1}{27} 3

t, x^{t} x^{3} = x^{6}

8 1^{8 x} = 3^{3 2^{7}}

(6 x)^{x} = 6^{6^{6}}

x, e^{x} = e - 1

What is the answer to 4*3^{7x}=9*2^{7x} ?
The answer to 4*3^{7x}=9*2^{7x} is x=(2ln(3)-2ln(2))/(7(-ln(2)+ln(3)))
Solve for x: 4*3^{7x}=9*2^{7x}
The solution is x=(2ln(3)-2ln(2))/(7(-ln(2)+ln(3)))