What is the answer to 4=e^{9(6)+c_{1}} ?

The answer to 4=e^{9(6)+c_{1}} is c_{1}=2ln(2)-54

Solve for e: 4=e^{9(6)+c_{1}}

The solution is c_{1}=2ln(2)-54

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4 = e^{9 (6) + c_{1}}

c_{1} = 2 ln (2) - 54

Decimal Notation

c_{1} = - 52.61370 \dots

Solution steps

4 = e^{9 (6) + c_{1}}

Apply exponent rules

ln (4) = 9 \cdot 6 + c_{1}

Solve

ln (4) = 9 \cdot 6 + c_{1} : c_{1} = 2 ln (2) - 54

c_{1} = 2 ln (2) - 54

x \cdot e^{- x} = 0

1.472 = 4 e^{b (- 2)}

3 2^{n} = 8

3 2^{n} = 1

What is the answer to 4=e^{9(6)+c_{1}} ?
The answer to 4=e^{9(6)+c_{1}} is c_{1}=2ln(2)-54
Solve for e: 4=e^{9(6)+c_{1}}
The solution is c_{1}=2ln(2)-54