What is the answer to 0=(1/2)^x-3 ?

The answer to 0=(1/2)^x-3 is x=-(ln(3))/(ln(2))

Solve for x: 0=(1/2)^x-3

The solution is x=-(ln(3))/(ln(2))

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0 = (\frac{1}{2})^{x} - 3

x = - \frac{ln ( 3 )}{ln ( 2 )}

Decimal Notation

x = - 1.58496 \dots

Solution steps

0 = (\frac{1}{2})^{x} - 3

Add

3

to both sides

0 + 3 = (\frac{1}{2})^{x} - 3 + 3

Simplify

3 = (\frac{1}{2})^{x}

Apply exponent rules

ln (3) = x ln (\frac{1}{2})

Solve

ln (3) = x ln (\frac{1}{2}) : x = - \frac{ln ( 3 )}{ln ( 2 )}

x = - \frac{ln ( 3 )}{ln ( 2 )}

4^{x^{2}} = 1 6^{5 x - 8}

1 6^{x} - 5 (2^{2 x - 1}) + 1 = 0

2 x^{2} e^{2 x} + 2 x e^{2 x} = 0

q, r^{q} = t^{s}

e^{l n (5 x)} = 2

What is the answer to 0=(1/2)^x-3 ?
The answer to 0=(1/2)^x-3 is x=-(ln(3))/(ln(2))
Solve for x: 0=(1/2)^x-3
The solution is x=-(ln(3))/(ln(2))