What is the answer to 4^{2x-1}=9^{-4x+5} ?

The answer to 4^{2x-1}=9^{-4x+5} is x=(10ln(3)+2ln(2))/(4ln(18))

Solve for x: 4^{2x-1}=9^{-4x+5}

The solution is x=(10ln(3)+2ln(2))/(4ln(18))

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4^{2 x - 1} = 9^{- 4 x + 5}

x = \frac{10 ln ( 3 ) + 2 ln ( 2 )}{4 ln ( 18 )}

Decimal Notation

x = 1.07014 \dots

Solution steps

4^{2 x - 1} = 9^{- 4 x + 5}

Apply exponent rules

(2 x - 1) ln (4) = (- 4 x + 5) ln (9)

Solve

(2 x - 1) ln (4) = (- 4 x + 5) ln (9) : x = \frac{10 ln ( 3 ) + 2 ln ( 2 )}{4 ln ( 18 )}

x = \frac{10 ln ( 3 ) + 2 ln ( 2 )}{4 ln ( 18 )}

e^{3 x - 1} = 1

e^{3 x - 1} = 8

- 8 \cdot 9^{- 5 x} = - 49

15000 = 10000 \cdot (1.1)^{x}

1 7^{3 x} = 3.1

What is the answer to 4^{2x-1}=9^{-4x+5} ?
The answer to 4^{2x-1}=9^{-4x+5} is x=(10ln(3)+2ln(2))/(4ln(18))
Solve for x: 4^{2x-1}=9^{-4x+5}
The solution is x=(10ln(3)+2ln(2))/(4ln(18))