What is the answer to 40=100*10^{-k^5} ?

The answer to 40=100*10^{-k^5} is k=-\sqrt[5]{(ln(2/5))/(ln(10))}

Solve for k: 40=100*10^{-k^5}

The solution is k=-\sqrt[5]{(ln(2/5))/(ln(10))}

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40 = 100 \cdot 1 0^{- k^{5}}

Decimal Notation

k = 0.83169 \dots

Solution steps

40 = 100 \cdot 1 0^{- k^{5}}

Switch sides

100 \cdot 1 0^{- k^{5}} = 40

Divide both sides by

100

1 0^{- k^{5}} = \frac{2}{5}

Apply exponent rules

- k^{5} ln (10) = ln (\frac{2}{5})

Solve

x, 3^{2 x} - 2^{2 y} - 713 = 0

x, 9^{x} - 2 (3^{x}) - 15 = 0

4^{x - 1} \cdot 5^{2 x + 3} = 6

3^{7 x + 1} = 6561

3^{2 x} - 3^{x} = 6

What is the answer to 40=100*10^{-k^5} ?
The answer to 40=100*10^{-k^5} is k=-\sqrt[5]{(ln(2/5))/(ln(10))}
Solve for k: 40=100*10^{-k^5}
The solution is k=-\sqrt[5]{(ln(2/5))/(ln(10))}