What is the answer to 2^x=3^{1-x} ?

The answer to 2^x=3^{1-x} is x=(ln(3))/(ln(6))

Solve for x: 2^x=3^{1-x}

The solution is x=(ln(3))/(ln(6))

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2^{x} = 3^{1 - x}

x = \frac{ln ( 3 )}{ln ( 6 )}

Decimal Notation

x = 0.61314 \dots

Solution steps

2^{x} = 3^{1 - x}

Apply exponent rules

x ln (2) = (1 - x) ln (3)

Solve

x ln (2) = (1 - x) ln (3) : x = \frac{ln ( 3 )}{ln ( 6 )}

x = \frac{ln ( 3 )}{ln ( 6 )}

5 = 10 e^{- 0.008 (x)}

3^{x} - 3^{x - 2} = a \cdot 3^{x}

e^{2 b} = b + 3

500000 = - 3 e^{- 5 x} + 35.156

What is the answer to 2^x=3^{1-x} ?
The answer to 2^x=3^{1-x} is x=(ln(3))/(ln(6))
Solve for x: 2^x=3^{1-x}
The solution is x=(ln(3))/(ln(6))