What is the answer to 4^{x+1}=8^{2x+3} ?

The answer to 4^{x+1}=8^{2x+3} is x=-7/4

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4^{x+1}=8^{2x+3}

4^{x + 1} = 8^{2 x + 3}

x = - \frac{7}{4}

Decimal Notation

x = - 1.75

Solution steps

4^{x + 1} = 8^{2 x + 3}

Apply exponent rules

2 (x + 1) = 3 (2 x + 3)

Solve

2 (x + 1) = 3 (2 x + 3) : x = - \frac{7}{4}

x = - \frac{7}{4}

(1000) 1.0 5^{3 x} = 3000

4 9^{x} = 21

320000 = 250342 e^{0.012 x}

3^{5 x + 34} = 81

0 = \frac{4 e ^{x}}{( 4 + e ^{x} ) ^{2}}

What is the answer to 4^{x+1}=8^{2x+3} ?
The answer to 4^{x+1}=8^{2x+3} is x=-7/4
Solve for x: 4^{x+1}=8^{2x+3}
The solution is x=-7/4