What is the answer to 2^{x-1}+2^{x+1}=320 ?

The answer to 2^{x-1}+2^{x+1}=320 is x=7

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2^{x-1}+2^{x+1}=320

2^{x - 1} + 2^{x + 1} = 320

x = 7

Solution steps

2^{x - 1} + 2^{x + 1} = 320

Factor

2^{x - 1} + 2^{x + 1} : 5 \cdot 2^{x - 1}

5 \cdot 2^{x - 1} = 320

Divide both sides by

5

2^{x - 1} = 64

Apply exponent rules

x - 1 = 6

Solve

x - 1 = 6 : x = 7

x = 7

3^{2 x} + 5 \cdot 3^{x} = 864

1.25 = 1.3 3^{x}

e^{x} = 5.7

2^{2} x - 6. 2^{x} + 8 = 0

2^{n} + 2^{n} = 2^{(n + 1)}

What is the answer to 2^{x-1}+2^{x+1}=320 ?
The answer to 2^{x-1}+2^{x+1}=320 is x=7
Solve for x: 2^{x-1}+2^{x+1}=320
The solution is x=7