What is the answer to 7^{-2x+9}=608 ?

The answer to 7^{-2x+9}=608 is x=(-ln(608)+9ln(7))/(2ln(7))

Solve for x: 7^{-2x+9}=608

The solution is x=(-ln(608)+9ln(7))/(2ln(7))

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7^{- 2 x + 9} = 608

x = \frac{- ln ( 608 ) + 9 ln ( 7 )}{2 ln ( 7 )}

Decimal Notation

x = 2.85291 \dots

Solution steps

7^{- 2 x + 9} = 608

Apply exponent rules

(- 2 x + 9) ln (7) = ln (608)

Solve

(- 2 x + 9) ln (7) = ln (608) : x = \frac{- ln ( 608 ) + 9 ln ( 7 )}{2 ln ( 7 )}

x = \frac{- ln ( 608 ) + 9 ln ( 7 )}{2 ln ( 7 )}

5^{x - 1} = 2 5^{- x + 2}

2^{x^{2} + x - 20} = 1

3 e^{3 x} (10 - 6 x) + e^{3 x} (- 6) = 0

e^{- x^{3}} = \frac{1}{e ^{x^{3}}}

8^{a} = 23

What is the answer to 7^{-2x+9}=608 ?
The answer to 7^{-2x+9}=608 is x=(-ln(608)+9ln(7))/(2ln(7))
Solve for x: 7^{-2x+9}=608
The solution is x=(-ln(608)+9ln(7))/(2ln(7))