What is the answer to 8^{4x}=5^{x-9} ?

The answer to 8^{4x}=5^{x-9} is x=-(9ln(5))/(12ln(2)-ln(5))

Solve for x: 8^{4x}=5^{x-9}

The solution is x=-(9ln(5))/(12ln(2)-ln(5))

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8^{4 x} = 5^{x - 9}

x = - \frac{9 ln ( 5 )}{12 ln ( 2 ) - ln ( 5 )}

Decimal Notation

x = - 2.15924 \dots

Solution steps

8^{4 x} = 5^{x - 9}

Apply exponent rules

4 x ln (8) = (x - 9) ln (5)

Solve

4 x ln (8) = (x - 9) ln (5) : x = - \frac{9 ln ( 5 )}{12 ln ( 2 ) - ln ( 5 )}

x = - \frac{9 ln ( 5 )}{12 ln ( 2 ) - ln ( 5 )}

- 10 \cdot 8^{- 5 n} = - 81

8^{x - 1} = 4^{x + 1}

e^{\frac{x}{5}} = 12

2^{4 x - 1} = 128

0.5 = c e^{30 k}

What is the answer to 8^{4x}=5^{x-9} ?
The answer to 8^{4x}=5^{x-9} is x=-(9ln(5))/(12ln(2)-ln(5))
Solve for x: 8^{4x}=5^{x-9}
The solution is x=-(9ln(5))/(12ln(2)-ln(5))