What is the answer to 6^{x+3}=8^{x-1} ?

The answer to 6^{x+3}=8^{x-1} is x=(3ln(12))/(ln(4/3))

Solve for x: 6^{x+3}=8^{x-1}

The solution is x=(3ln(12))/(ln(4/3))

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6^{x + 3} = 8^{x - 1}

x = \frac{3 ln ( 12 )}{ln ( \frac{4}{3} )}

Decimal Notation

x = 25.91305 \dots

Solution steps

6^{x + 3} = 8^{x - 1}

Apply exponent rules

(x + 3) ln (6) = (x - 1) ln (8)

Solve

(x + 3) ln (6) = (x - 1) ln (8) : x = \frac{3 ln ( 12 )}{ln ( \frac{4}{3} )}

x = \frac{3 ln ( 12 )}{ln ( \frac{4}{3} )}

160 \cdot e^{x} - x = 0

x, lo g_{3} (7^{5 x}) = 10

2^{3 x + 1} = 4^{x - 2}

7^{- 4 x} = 8

2^{x + 2} - 2^{x} = 24

What is the answer to 6^{x+3}=8^{x-1} ?
The answer to 6^{x+3}=8^{x-1} is x=(3ln(12))/(ln(4/3))
Solve for x: 6^{x+3}=8^{x-1}
The solution is x=(3ln(12))/(ln(4/3))